Question 1177327
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Hi
1/3, 1, 3, 9... 
{{{a[n] = a[1]*r^(n-1)}}}
{{{a[2] =(1/3)*r^1 = 1}}}  r = 3
{{{a[n] = (1/3)*3^(n-1)}}}
{{{a[9] = (1/3)*3^(8)}}} = 2187

Wish You the Best in your Studies.
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