Question 859388
x = smallest integer


x(x+1) + (x + (x+1)) = 41
x^2 + x + 2x + 1 = 41
x^2 + 3x - 40 = 0
(x + 8)(x - 5) = 0
x = -8, x = 5


x is negative, so the integers are -8 and -7.