Question 850321
consecutive odd integers: (x-2), x, (x+2)


(x-2)^2 + x^2 = (x+2)^2 + 65
x^2 - 4x + 4 + x^2 = x^2 + 4x + 4 + 65
2x^2 - 4x + 4 = x^2 + 4x + 69
x^2 - 8x - 65 = 0
(x - 13)(x + 5) = 0
x = 13, x = -5


x is positive, so the integers are 11, 13, and 15.