Question 795514
consecutive odd integers: x, (x+2)


x^2 + (x+2)^2 = 130
x^2 + x^2 + 4x + 4 = 130
2x^2 + 4x - 126 = 0
x^2 + 2x - 63 = 0
(x + 9)(x - 7) = 0


The integers could be -9 and -7 or 7 and 9.