Question 801418
consecutive positive even integers: x, (x+2)


x(x+2) = 16 + 16(x+1)
x^2 + 2x = 16x + 32
x^2 - 14x - 32 = 0
(x - 16)(x + 2) = 0
x = 16, x = -2


x is positive, so the integers are 14, 16, and 18.