Question 807080
consecutive odd positive integers: (x-2), x, (x+2)


2((x-2) + x + (x+2)) = 7 + (x-2)(x)
6x = 7 + x^2 - 2x
0 = x^2 - 8x + 7
0 = (x - 1)(x - 7)


The numbers are all positive, so x = 7 and the numbers are 7, 9, and 11.