Question 110650


In general
 
{{{logb (x) = y}}}
  
where

{{{ b^y = x }}}

So, we can find the value of x this way: 

{{{log5 (625) = x}}}

{{{5^x = 625}}} 

{{{x = 4}}}

Check:

{{{5^4 = 5*5*5*5 = 625}}}