Question 828983
consecutive even integers: (x-2), x, (x+2)


(x-2)^2 + x^2 = (x+2)^2 + 20
x^2 - 4x + 4 + x^2 = x^2 + 4x + 4 + 20
x^2 - 4x = 4x + 20
x^2 - 8x - 20 = 0
(x - 10)(x + 2) = 0
x = 10, x = -2


The integers could be {-4, -2, 0} or {8, 10, 12}.