Question 828982
consecutive odd integers: (x-2), x, (x+2)


2((x-2) + x + (x+2)) = (x-2)(x) - 9
2(3x) = x^2 - 2x - 9
6x = x^2 - 2x - 9
0 = x^2 - 8x - 9
0 = (x - 9)(x + 1)
x = 9 or x = -1


The integers could be {7, 9, 11} or {-3, -1, 1}.