Question 943384

find three positive consecutive odd integers such that the square of the smallest is 9 more than the sum of the other two
<pre>With the fist being F, that's SIMPLY F<sup><b>2</sup></b> = F + 2 + F + 4 + 9 , which forms the following quadratic equation: F<sup><b>2</sup></b> - 2F - 15 = 0, and the first ODD INTEGER, 5. 
Now, the others are easy to decipher.