Question 841111
x-1, x, x+1



(x+1)^2 = 5 + 4(x-1 + x)
x^2 + 2x + 1 = 5 + 8x - 4
x^2 - 6x = 0
x(x - 6) = 0
x = 0, x = 6


The integers could be {-1, 0, 1} or {5, 6, 7}.