Question 857468
x = 4y
z = x + 6
x + y + z = x + 46 



x + y + z = x + 46
y + z = 46
x/4 + z = 46 (eqn 1)
-x + z = 6 (eqn 2)


Subtract eqn 2 from eqn 1.


x/4 + z = 46
x - z = -6
-------------
5x/4 = 40 ---> x = 32


The integers are (x, y, z) = (32, 8, 38).