Question 861084
x = 2y + 3
xy = 27


Substitute x = 2y + 3 into the second equation.


(2y + 3)(y) = 27
2y^2 + 3y - 27 = 0
(2y + 9)(y - 3) = 0
y = -9/2 or y = 3


Solutions: (x, y) = (-6, -9/2) or (9, 3)