Question 862362
consecutive odd integers: (x-2), x, (x+2)


(x-2)(x+2) < 7x
x^2 - 4 < 7x
x^2 - 7x - 4 < 0


integer solutions: x = 0, 1, 2, 3, 4 ---> odd: 1, 3


The integers have to be positive, so the integers are 1, 3, and 5.