Question 901995
consecutive odd integers: x, (x+2)


x(x+2) = 107 + 6(x + (x+2))
x^2 + 2x = 6(2x+2) + 107
x^2 + 2x = 12x + 119
x^2 - 10x - 119 = 0
(x - 17)(x + 7) = 0


The integers are -7 and -5 or 17 and 19.