Question 899228
consecutive odd integers: x, (x+2)


x(x+2) = 6(x + (x+2)) - 1
x^2 + 2x = 6(2x+2) - 1
x^2 + 2x = 12x + 11
x^2 - 10x - 11 = 0
(x - 11)(x + 1) = 0


The integers are -1 and 1 or 11 and 13.