Question 904766
consecutive integers: (x-1), x, (x+1)


(x-1)(x+1) = 4x + 20
x^2 - 1 = 4x + 20
x^2 - 4x - 21 = 0
(x + 3)(x - 7) = 0


The integers could be {-4, -3, -2} or {6, 7, 8}.