Question 1177011
i think 40.
if she had 8 dogs she could have given each dog 5 bones because 8 * 5 = 40.
she only has 7 dogs.
6 bones each would require 42.
since she only has 40, she would need 2 more to give each of her 7 dogs the same number of bones.


to be enough to give each of 8 dogs the same number of bones, she would need to buy bones in multiples of 8.


if she buys 8 bones, she can feed 7 dogs 1 bone each and have 1 left over.
she will be 6 short from feeding 7 dogs 2 bones each.


if she buys 16 bones, she can feed 7 dogs 2 bones each and have 2 left over.
she will be 5 short from feeding 7 dogs 3 bones each.


if she buys 24 bones, she can feed 7 dogs 3 bones each and have 3 left over.
she will be 4 short from feeding 7 dogs 4 bones each.


if she buys 32 bones, she can feed 7 dogs 4 bones each and have 4 left over.
she will be 3 short from feeding 7 dogs 5 bones each.


if she buys 40 bones, she can feed 7 dogs 5 bones each and have 5 left over.
she will be 2 short from feeding 7 dogs 6 bones each.


she more then likely bought 40 bones.
8 dogs would have had 5 bones each.
7 dogs would have 5 bones each with 5 bones left over.
with another 2 bones, she could feed each dog 6 bones each.


i believe this is the answer you are looking for, if i understand the problem correctly.