Question 913520
x^2 + y^2 = 521
x = 2y - 2


Substitute x = 2y - 2 into the first equation.


(2y - 2)^2 + y^2 = 521
4y^2 - 8y + 4 + y^2 = 521
5y^2 - 8y - 517 = 0
(5y + 47)(y - 11) = 0


y is positive, so y = 11 and x = 20.


The smaller integer = y = 11.