Question 1060610
4(x-3)^2 - 8(x-3)
= 4(x-3)(x-3) - 8(x-3)
= 4(x-3)((x-3) - 2)
= 4(x-3)(x-5)


4(x-3)^2 - 8(x-3) - 4(x-3)(x-5)
= 4(x^2 - 6x + 9) - (8x - 24) - 4(x^2 - 8x + 15)
= (4x^2 - 24x + 36) - 8x + 24 - 4x^2 + 32x - 60
= -24x + 36 - 8x + 24 + 32x - 60
= 0