Question 931465
consecutive positive integers: (x-1), x, (x+1)


(x-1)(x+1) = 6x - 1
x^2 - 1 = 6x - 1
x^2 - 6x = 0
x(x - 6) = 0


The integers are positive, so x = 6 and the integers are 5, 6, and 7.