Question 943184
consecutive odd integers: (x-2), x, (x+2)


(x-2)^2 + x^2 + (x+2)^2 = 3(x-2)(x+2) + 20



(x^2 - 4x + 4) + x^2 + (x^2 + 4x + 4)
= 3x^2 + 8
= 3(x^2 - 4) + 20
= 3(x-2)(x+2) + 20