Question 959492
x = larger number
y = smaller number


x = 2y + 9
xy = 3(x + y) + 5


Substitute x into the second equation.


(2y + 9)(y) = 3(2y + 9 + y) + 5
2y^2 + 9y = 3(3y + 9) + 5
2y^2 + 9y = 9y + 32
2y^2 = 32
y^2 = 16
y = 4 or -4


The integers are (x, y) = (17, 4) or (1, -4)