Question 950653
consecutive even integers: (x-2), x, (x+2)


(x-2)(x+2) = 8x - 4
x^2 - 4 = 8x - 4
x^2 - 8x = 0
x(x - 8) = 0


The integers could be {-2, 0, 2} or {6, 8, 10.}