Question 1022609
consecutive positive integers: (x-1), x, (x+1)


x(x+1) = 2x + 2((x-1) + x + (x+1))
x^2 + x = 2x + 6x
x^2 - 7x = 0
x(x-7) = 0
x = 0, 7


The integers are positive, so the integers are 6, 7, and 8.