Question 953763
consecutive integers: x, (x+1)


x + (x+1) = 5/6 * (x(x+1))
2x + 1 = 5x^2/6 + 5x/6
0 = 5x^2/6 - 7x/6 - 1
0 = 5x^2 - 7x - 6
0 = (x - 2)(5x + 3) = 0


The numbers are integers, so x = 2.


The integers are 2 and 3.