Question 110549
{{{3x/5-2y=5}}}
But, {{{x=4y/5+2}}}. So,

{{{3(4y/5+2)/5-2y=5}}}
{{{(12y/5+6)/5-2y=5}}}
{{{5((12y/5+6)/5-2y)=5*5}}}
{{{(12y/5+6)-10y=25}}}
{{{5((12y/5+6)-10y)=5*25}}}
{{{12y+30-50y=125}}}
{{{12y-50y+30=125}}}
{{{-38y+30=125}}}
{{{-38y+30-30=125-30}}}
{{{-38y+0=95}}}
{{{-38y=95}}}
{{{y=-5/2}}}


again, {{{x=4/5y+2}}}. So,

{{{x=4(-5/2)/5+2=-10/5+2=-2+2=0}}}


Thus,

{{{x=0}}} and {{{y=-5/2}}}


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