Question 959895
consecutive positive integers: (x-1), x, (x+1)


(x-1)^3 - 5(x+1)^2 = 5 + 3x
x^3 - 3x^2 + 3x - 1 - (5x^2 + 10x + 5) = 3x + 5
x^3 - 8x^2 - 7x - 6 = 3x + 5
x^3 - 8x^2 - 10x - 11 = 0


This equation has no integer solutions.