Question 963075
consecutive even integers: (x-2), x, (x+2)


(x-2)(x) = 5(x+2) - 2
x^2 - 2x = 5x + 8
x^2 - 7x - 8 = 0
(x - 8)(x + 1) = 0


x is even, so x = 8.


The integers are 6, 8, and 10.