Question 1177165

a line with the slope, {{{m=4/3}}}, which passes through the point ({{{-1}}}, {{{-6}}})

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} y-intercept


{{{y=mx+b}}} ...substitute {{{m=4/3}}}

{{{y=(4/3)x+b}}} ..........use given point to find {{{b}}}

{{{-6=(4/3)(-1)+b}}} 

{{{-6=-(4/3)+b}}} 

{{{-6+(4/3)=b}}} 

{{{-18/3+4/3=b}}} 

{{{b=-14/3}}}


your equation is

{{{y=(4/3)x-14/3}}} 


{{{drawing( 600, 600, -10, 10, -10, 10, 
circle(-1,-6,.12),locate(-1,-6,p(-1,-6)),
  graph( 600, 600, -10, 10, -10, 10, (4/3)x-14/3)) }}}