Question 1177113
<pre>
{{{Probability = (successes)/(successes+ failures)}}}

{{{(matrix(3,1,odds,in,favor))}}}{{{""=""}}}{{{"successes:failures"}}}

{{{(matrix(2,1,odds,against))}}}{{{""=""}}}{{{"failures:successes"}}}

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For A:

{{{Probability = (successes)/(successes+ failures)=5/11}}}

So successes = 5, failures = 11-5 = 6


{{{(matrix(3,1,odds,in,favor))}}}{{{""=""}}}{{{"5:7"}}}

{{{(matrix(2,1,odds,against))}}}{{{""=""}}}{{{"7:5"}}}

For B:

{{{Probability = (successes)/(successes+ failures)=3/4}}}

So successes = 3, failures = 4-3 = 1


{{{(matrix(3,1,odds,in,favor))}}}{{{""=""}}}{{{"3:1"}}}

{{{(matrix(2,1,odds,against))}}}{{{""=""}}}{{{"1:3"}}}

Edwin</pre>