Question 994756
Using some guessing and checking, we see that the integers are 7 and 8.


Here is a more algebraic approach:


smaller integer = x


x(x+1) = 56
x^2 + x = 56
x^2 + x - 56 = 0
(x + 8)(x - 7) = 0


x is positive, so x = 7.