Question 994938
4 consecutive integers: x, (x+1), (x+2), (x+3)


3(x + 3) + 9 = 2(x + (x+1)) + 6
3x + 9 + 9 = 2(2x + 1) + 6
3x + 18 = 4x + 8
10 = x


sum of all integers = x + (x+1) + (x+2) + (x+3) = 10 + 11 + 12 + 13 = 46