Question 1177055
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Hi
12games:  A wins 6, B wins 4, 2 T
Play 3 games:
a) P(A wins all three games) = (1/2)(1/2)(1/2) = 1/8
b) P(Two games end in a tie) =  (3C2)(5/6)(1/6)(1/6) = 15/216
c) P(A and B wins alternatively) =  
P(ABA) + P(BAB) = (1/2)(1/3)(1/2) + (1/3)(1/2)(1/3) = 1/12 + 1/18 =  30/12*18 = 5/36

d) P( B wins at least one game) = 1 - P(wins NO games) = 1- 1/8 = 7/8

Wish You the Best in your Studies.
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