Question 1177052
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Hi
the probability of getting 4,5, or 6 on the first toss 
and a 1,2,3 or 4 on the second toss.

 P = 12/36 = 1/3

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) 

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) 

<u>(4,1) (4,2) (4,3) (4,4)</u> (4,5) (4,6) 

<u>(5,1) (5,2) (5,3) (5,4)</u> (5,5) (5,6) 

<u>(6,1) (6,2) (6,3) (6,4)</u> (6,5) (6,6)

Wish You the Best in your Studies.
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