Question 1176982
Let f(x)=4-x^2. The equation of the tangent line to the curve at (1,3) is 2x+y=5.


a. What is the slope of the tangent line to the curve at (1,3)?
---
The slope is -2, as shown in part b.
----
Or,
2x+y=5
y = -2x + 5
Slope = -2
=======================================================
b. What is the derivative of the function when x=1?
------------------
f'(x) = -2x
f'(1) = -2