Question 1176991
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ F\ =\ Pe^{rt}]


Plugin your numbers


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 8000e^{18r}\ =\ 13006.40]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ e^{18r}\ =\ \frac{13006.40}{8000}]


Take the natural log of both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ln\(e^{18r}\)\ =\ \ln\(\frac{13006.40}{8000}\)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 18r\ln\(e\)\ =\ \ln\(\frac{13006.40}{8000}\)]


Since *[tex \LARGE \ln e\ =\ 1]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ =\ \frac{\ln\(\frac{13006.40}{8000}\)}{18}]


You can do your own arithmetic.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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