Question 1176929
<br>
Incorrect statement of the problem....<br>
The given first three terms form a linear sequence, not a quadratic sequence.  Graphed as the three points (1,1), (2,3), and (3,5), the three points will lie on a straight line; no quadratic will ever contain three points in a straight line.<br>
So if the sequence is quadratic, the given first three terms are not right.<br>
And if the given first three terms are right and the sequence is linear, then the 7th term is not 35.<br>
So nothing can be done with the given information....<br>