Question 1176927
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The average number of homes sold by the GBRAR is four (4) homes per day. 
What is the probability that exactly six (6) homes will be sold tomorrow?
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            The problem does not state that the only Poisson distribution can be used.


            Therefore,  totally different  (but still reasonable approach)  can be developed and applied.



<pre>
Let's consider a random discrete variable X of the number of sold homes with integer values 
from 0 to 8 inclusive, uniformly distributed.


Such random variable satisfies the given restriction, having 4 homes per day as the average.


Then we have the discretely distributed random variable having 9 possible values from 0 to 8 inclusive
with the probability  {{{1/9}}}  for each discrete individual value.


Then  P(X=6) = {{{1/9}}} = 0.1111...         <U>ANSWER</U>
</pre>

Solved &nbsp;(differently).


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What is interesting, &nbsp;this answer of &nbsp;0.1111 &nbsp;is not too far from the value of &nbsp;0.1042, 
obtained by &nbsp;@Boreal with the use of the &nbsp;Poisson distribution.