Question 110455
what you have is a right triangle with sides (4+2)=6 in the y direction 
& (1+3)=4 in the x direction.
seeing as we're looking for the hypotenuse of this right triangle we use the pythagorean therom:a^2+b^2=c^2
6^2+4^2=c^2
36+16=c^2
c^2=52
c=sqrt52
c=7.21 is the distance between these 2 points.