Question 110441
You don't say what the question is.  What you have is a single linear equation in two variables, so the only things you can do are graph it, and determine the slope and the intercepts.  If there is a specific question, please share it.
:
{{{y+4=(2/3)(x+12)}}}
:
First put the equation in slope-intercept form {{{y=mx+b}}}
:
{{{y+4=2x/3+8}}}
{{{y=2x/3+4}}}
:
Now you know the slope of the line is 2/3, and the y-intercept (the point where the line crosses the y-axis) is 4.
:
And here is a graph of the line:
:
{{{graph(400,400,-6,6,-6,6,2x/3+4)}}}
:
Also note that the coordinates of any point that lies on the line will satisfy the given equation, and the coordinates of any other point will make the statement false.
:
For example, the point (-6,0) is on the line.  {{{0=(2*-6)/3+4}}} is a true statement.  On the other hand the point (1,1) is NOT on the line.  {{{1=(2*1)/3+4}}} is a false statement.