Question 110375
{{{log3( 3.5)}}} ........the argument is {{{3.5}}}and the base is {{{3}}}

 Plug them into {{{change-of-base}}} formula; 

{{{logb(x) = logd(x)/logd(b)}}}

 I will use the natural log

{{{log3( 3.5)=ln(3.5)/ln(3) }}} 

{{{log3( 3.5)=ln(3.5)/ln(3) }}}

 {{{log3( 3.5)=0.54406804435/ 0.47712125472  }}}

 {{{log3( 3.5)=1.1403139955885803468654996246653}}}


Then the answer, rounded to three decimal places, is:

{{{log3( 3.5)=1.140}}}