Question 1176834
<br>
Informally....<br>
70 = 2*5*7 so height 2, width 5, length 7<br>
Algebraically....<br>
x = width
x+2 = length
x-3 = height<br>
The volume is 70:<br>
{{{x(x+2)(x-3) = 70}}}
{{{x^3-x^2-6x = 70}}}
{{{x^3-x^2-6x-70 = 0}}}<br>
What you do with that is up to you.<br>
I would graph the function on a graphing calculator to find the x value that makes the function value 0.<br>
Or I might solve the problem informally to find the width is 5, as shown above, and then verify that that answer gives the right volume.<br>