Question 1176831
I'm assuming that the first part is what height does it reach.  What it does not reach is everything else.
h(t)=-5t^2+30t+1
vertex is at x=-b/2a or -30/-10 or at 3 seconds for t
h(3)=-45+90+1 or 46 m height reached.
set that equation equal to 1
there are two places where h(t)=1, at the bat and when caught.
so h(t)=-5t^2+30t=-5t(t-6)=0
t=6.0 seconds, twice the time to get to the vertex, since this is symmetric at h(t)=1 m
{{{graph(300,300,-5,10,-10,50,1+30x-5x^2,46,1)}}}