Question 1176829

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

given:of the line through the points (-5,1) and (5,4)

line passing through ({{{-5}}}, {{{1}}}) and  ({{{5}}},{{{4}}})

use points to find slope

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(4-1)/(5-(-5))}}}

{{{m=3/(5+5-2)}}}

{{{m=3/10}}}

so far equation is


{{{y= (3/10)x+b}}} .......us a point ({{{5}}},{{{4}}}) to find {{{b}}}

{{{4= (3/10)5+b}}} 

{{{4= 15/10+b}}} 

{{{4-15/10=b}}}

{{{b=5/2}}}


and your equation is

{{{y= (3/10)x+5/2}}}

{{{drawing( 600, 600, -10, 10, -10, 10,
circle(5,4,.12),locate(5,4,p(5,4)),
circle(-5,1,.12),locate(-5,1,p(-5,1)),
 graph( 600, 600, -10, 10, -10, 10,(3/10)x+5/2)) }}}