Question 1176814

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

given:

line passing through ({{{1}}}, {{{-6}}}) 

with x-intercept = {{{-1}}}-> point ({{{-1}}},{{{0}}})

use points to find slope

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(0-(-6))/(-1-1)}}}

{{{m=6/(-2)}}}

{{{m=-3}}}

so far equation is


{{{y= -3x+b}}} .......us a point ({{{-1}}},{{{0}}}) to find {{{b}}}

{{{0= -3(-1)+b}}} 

{{{0= 3+b}}} 

{{{b=-3}}}


and your equation is

{{{y= -3x-3}}}

or

{{{y= -3(x+1)}}}


equation in slope point form:

{{{y-y[1]=m(x-x[1])}}} .......now use a slope and point ({{{1}}}, {{{-6}}}) 

{{{y-(-6)=-3(x-1)}}}

{{{y+6=-3(x-1)}}}


so, answer is: {{{y + 6=-3(x-1)}}} or {{{y = -3(x+1)}}}