Question 1176819

Negative leading coefficient with an odd degree: 


Zeros at {{{x = -3}}} with multiplicity {{{4}}}, 
{{{x-(-3)=x+3}}}=> you have {{{4}}} times factor {{{(x+3)}}} or {{{(x+3)^4}}}

{{{x = 0}}} with multiplicity 1,
 {{{x-0=x}}}=> you have {{{1}}} time factor {{{x}}}

{{{x = 3}}} with multiplicity 2 
{{{x-3}}}=> you have {{{2}}} times factor {{{(x-3)}}}, or {{{(x-3)^2}}}

then your polinomial is equal to product of the factors above multiplied by {{{-1}}} because negative leading coefficient :

{{{f(x)=-((x+3)^4*x*(x-3)^2)}}}

{{{f(x)=-x^7 - 6x^6 + 9x^5 + 108x^4 + 81x^3 - 486x^2 - 729x}}}


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