Question 487617
Let ln(x) = y.


3y^3 - 4y^2 - 5y + 2 = 0
(y - 2)(3y - 1)(y + 1) = 0


y = 2, y = 1/3, or y = -1


ln(x) cannot be negative, eliminating the last case.


ln(x) = 2 ----> x = e^2
ln(x) = 1/3 ----> x = 1/(e^3)