Question 1176780
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Hi
Previously submitted:
perpendicular to line  x−5y−4=0  0r y = x/5-4/5 , m = 1/5
Slope of New Line is -5  (negative reciprocal)
Passing through (5,−3)
 y + 3 = -5(x - 5)   Point-slope form

  y = -5x -28   Slope Intercept Form
Wish You the Best in your Studies. 
{{{drawing(300,300,    -30,30,-30,30,   
 grid(1),
circle(0, 22,0.4),
circle(0,-4/5,0.4),
graph( 300, 300, -30,30,-30,30,0, -5x -28 , x/5  - 4/5))}}}