Question 1046401
3^x = y


2y^2 - 8 = 2y + 1
2y^2 - 2y - 9 = 0


Use the quadratic formula: y = 1/2 + sqrt(19)/2 or 1/2 - sqrt(19)/2.


y has to be positive, so: x^3 = 1/2 + sqrt(19)/2


x = (1/2 + sqrt(19)/2)^(1/3)